As per the Hardy-Schulze rule,the flocculatio | vedclass

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(D) $Fe(OH)_{3}$ sol is a positively charged sol. Therefore,it is coagulated by the anions of the added electrolytes.According to the Hardy-Schulze ru

Vedclass · Accepted Answer

$K_{3}[Fe(CN)_{6}] < K_{2}CrO_{4} < KBr = KNO_{3} < AlCl_{3}$

Vedclass · Answer

(D) $Fe(OH)_{3}$ sol is a positively charged sol. Therefore,it is coagulated by the anions of the added electrolytes.According to the Hardy-Schulze rule,the coagulating power of an ion increases with the increase in the magnitude of its charge.The order of coagulating power of the anions is: $[Fe(CN)_{6}]^{3-} > CrO_{4}^{2-} > Cl^{-} = Br^{-} = NO_{3}^{-}$.Since the coagulating power is inversely proportional to the flocculation value,the order of flocculation values is: $K_{3}[Fe(CN)_{6}] < K_{2}CrO_{4} < KBr = KNO_{3} < AlCl_{3}$.

As per the Hardy-Schulze rule,the flocculation values of the following electrolytes for a ferric hydroxide sol are in the order:

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